Cognizant Interview
Cognizant is a multinational corporation that provides IT services to different organizations, including digital technology, consulting, operations and all kind of services. It is headquartered in Teaneck, New Jersey, United States. It was founded as in-house technology unit of Dun & Bradstreet in 1994 and started serving external organizations as clients in 1996.
It offers the unique learning and work environment with their great learning materials.
Cognizant provides an intelligent, digital and tactical approach that transforms the way business gets done without interrupting business as usual. Services provided by Cognizant are like information technology, information security, consulting, ITO and BPO services. These include business & technology consulting, systems integration, application development & maintenance, IT infrastructure services, analytics, business intelligence, data warehousing, customer relationship management, engineering & manufacturing solutions, research, and development outsourcing, and testing solutions.
Cognizant has many branches in all over the India as well as outside India.
Cognizant recruits its employees in two ways:
1. On-campus Recruitment
https://techzone360.shop/cognizant-interview-questions/
- Aptitude
- Programming
- HR
2. Off-campus Recruitment
- Aptitude
- Programmin
Cognizant Interview Pattern for On-campus drives:
1. Logical Reasoning
- Questions – 14
- Time – 14 minutes
- Difficulty – High
- Cut-Off – 70%
2. Quantitative Aptitude
- Questions – 16
- Time – 16 minutes
- Difficulty – Medium
- Cut-Off – 70%
3. Verbal Ability
- Questions – 25
- Time – 25 minutes
- Difficulty – Medium
- Cut-Off – 70%
4. Automata Fix
- Questions – 7
- Time – 20 minutes
- Difficulty – High
- Cut-Off – 70%
Cognizant Interview Pattern for Off-campus drives:
1. Aptitude Questions
- Questions – 16
- Time – 16 minutes
- Difficulty – High
- Cut-Off – 70%
2. Logical Questions
- Questions – 14
- Time – 14 minutes
- Difficulty – Medium
- Cut-Off – 70%
3. English Questions
- Questions – 25
- Time – 25 minutes
- Difficulty – Medium
- Cut-Off – 70%
4. Coding Questions
- Questions – 2
- Time – 60 minutes
- Difficulty – Medium
- Cut-Off – 70%
Cognizant First Round
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Aptitude & Logical Questions
1) The product of 2 numbers is 2028, and the H.C.F. is 13. The number of such pairs is:
- 3
- 2
- 6
- 9
Hide Answer
Answer: b
Solution:
Let the numbers 13a and 13b.
Then, 13a x 13b = 2028
=> a * b = 12.
Now, the co-primes with the product 12 are (1, 12) and (3, 4). So, the required numbers is (13 x 1, 13 x 12) and (13 x 3, 13 x 4).There are two such pairs
2) Find the biggest digit which on dividing 1657 and 2037 leaves the remainders 6 and 5 respectively is:
- 156
- 127
- 135
- 115
Hide Answer
Answer: b
Solution:
The number we require = H.C.F. of (1657 – 6), (2037 – 5) =H.C.F. of 1651 and 2032 = 127.
3) The L.C.M of 2 numbers is 495, and the H.C.F is 5. If the sum of these numbers is 100, then their difference is,
- 10
- 46
- 70
- 90
Hide Answer
Answer: a
Solution:
Let the numbers be x and (100-x).
Then, x*(100-x) = 5*495-100-x = 5*495
x2-100x+2475=0x2-100x+2475 = 0
(x – 55)*(x – 45) = 0
x = 55 or x = 45
The numbers are 45 and 55
Required difference = (55-45) = 10.
4) H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is
- 12
- 48
- 84
- 108
Hide Answer
Answer: c
Solution:
Let the numbers be x and 4x. Then, x�4x=84�21 ?
x2=84�214? x=21x�4x=84�21 ? x2=84�214? x=21
Hence Larger Number = 4x = 84.
5) The smallest number is given which is a perfect square and contains 7936 as a factor is:
- 251664
- 231564
- 246016
- 346016
Hide Answer
Answer: c
Solution:
7936 => 2^2 * 2^2 * 2^2 * 2^2 * 31^1
To make it as a perfect square, we have to multiply
7936 with 31….
Hence the read no. is 7936*31 = 246016.
6) P is an integer. P is greater than 994. If P -7 is a multiple of 11, then the largest number that will always divide (P+4)(P+15) is
- 242
- 343
- 321
- none
Hide Answer
Answer: a
Solution:
p-7= 11*a (as it is multiple of 11)
p=11*(a+7)
So (p+4)*(p+15) = (11a+7+4)*(11a+7+15);
= (11a+11)*(11a+22);
=11*11(a+1)*(a+2);
=121*2
=242
7) The greatest number that will divide 65, 134 and 224 to leave the same remainder in each case:
- 3
- 7
- 5
- 9
Hide Answer
Answer: a
Solution:
The greatest number = H.C.F of (134-65), (224-134),
(224-65)
H.C.F of 69, 90 and 159 = 3.
15 is the greatest number.
8) What is the smallest four-digit number which when divided by 6, leaves a remainder of 4 and when divided by 4 leaves a remainder of 3?
- 1043
- 1073
- 1103
- None of these
Hide Answer
Answer: d
Solution:
remainder when m is divided by 4 = 2
Smallest m is 2.
Hence, N = 1001 + 6 * 2 = 1013.
9) Sum of money given to a man at compound interest doubles itself within six years. In how much time will it amount to eight times itself?
- 16
- 24
- 18
- 20
Hide Answer
10) A set sum of money amounts to Rs.1500 in 2 years and Rs. 1726 in 4 years. Find the sum
- Rs850, 10%
- Rs900, 12%
- Rs800, 13%
- Rs1274, 15%
Hide Answer
Answer: d
Solution:
1726-1500= 226 for 2 years (4-2) so for one year 226/2= 113 then for 2 years interest is 113+113=226 Then principal 1500-226=1274. Now 113/1274*100= 15%.
11) Mina drives from her home to the nearest bus station at an average speed of 80km/h. From the bus station, she boards a bus that takes to her office at a speed of 120km/h. The entire distance covered by her is 92km, and the entire journey took her 1 hour. Find the distance between the bus station from where she boards the bus and her office.
- 91.97
- 94.65
- 83.97
- 92.78
Hide Answer
Answer: a
Explanation:
Let from her home to station distance = X, so,
(X \ 80) + ((92-X)/120) = 1
Solving this X = 183.97 km
So from office to station = 183.97-92 = 91.975 km
12) Straight line between 2 places is 3000m. A person moves with 6/11km/hour from p to q @12pm and another person moves from opposite direction with speed 5/22km/hour from q to p @ 1pm.when they will meet together?
- 4.18pm
- 4.17pm
- 8.15am
- 9.10pm
Hide Answer
Answer: b
Solution:
The person from p moves 6/11 km in 1 hour so 3-6/11=27/11
6/11 t+5/22 t=27/11
17/22 t=27/11
t=54/17 =3.17hso, time=4:17 pm
13) A 270-meter long train running at the speed of 120 km/h crosses the second train running in the opposite direction with the speed of 80 km/h in 9 seconds. What is the length of the second train?
- 360meter
- 260meter
- 270meter
- 230meter
Hide Answer
Answer: d
Solution:
train running in the opposite than total speed= (80+120) = 200 km/h
200kmph=200*5/18=500/9 m/set the length of another train is l meter than
(270+l)/9=500/9
Length (l) =230 meter.
14) How many seconds will a 500-meter long train moving with a speed of 63 km/hour, take to cross a man walking at a speed of 3 km/hour in the direction of the train?
- 42
- 50
- 30
- 28
Hide Answer
Answer: c
Solution:
train and man is moving in the same direction so the relative speed will be = (63-3) km/hour = 60 km/hour
Then 60 km/hour * 5/18= 50/3 m/sec
Therefore, time = distance/speed
= 500/ (50/3)
= 30 seconds
So the answer is 30 seconds.
15) If ax = by, then:
- log(a/b) = x/y
- log(a) / log(b) = x/y
- log(a) / log(b) = y/x
- None of these
Hide Answer
Answer: c
16) If log x + log y = log (x + y), then:
- x = y
- x*y=1
- y = (x-1)/x
- y = x/(x-1)
Hide Answer
Answer: d
Solution:
log x + log y = log (x + y)
log(x*y) = log (x + y)*x*y = x + y
x*y – y = x
(x – 1)*y = x, y = x/(x-1).
17) If 0.5(log a + log b) = log{(a + b)/3}, then define the relation between a and b is:
- a2+b2 = 7ab
- a2-b2 = 7ab
- (a + b)2 = 2
- (a + b)/3 = (1/2)(a +b)
Hide Answer
Answer: a
Solution:
0.5[log(a) + log(b)] = Log[(a + b)/3]
0.5*log(a*b) = log[(a + b)/3]
log[sqrt(a*b)] = log[(a + b)/3]
sqrt(a*b) = (a + b)/3
3*sqrt(a(b) = a + b
9 *a*b = a^2 + 2ab + b^2
7*a*b = a^2 + b^2
18) If log x = log 3 + 2 log 2- (3/4) log 16. The value of x is:
- ½
- 1
- 3/2
- 2
Hide Answer
Answer: c
Solution:
log x= log 3+ 2 log 2 – (3/4)log 16.
log x = log 3 + 2 log 2 – (3/4) log 2^4.
log x = log 3 + 2 log 2 – (3*4)/4 log 2.
log x = log 3 + 2 log 2 – 3 log 2.
log x = log 3 – log 2.
log x = log 3/2.
So, x = 3/2.
19) If log x = (1/2) log y = (1/5) log z, the value of x4y3z-2 is:
- 0
- 8
- 1
- 5
Hide Answer
Answer: c
Solution:
log(x) = (1/2) log(y) => y = x^2
log(x) = (1/5) log(z) => z = x^5
Then x^4*y^5*z^-2 = x^4*x^6*x^-10 = x^10 * x^-10 = x^0 = 1,
If any value has power value as 0 then its overall value is 1.
20) If log10000 x = -1/4, then x is given by:
- 1/100
- 1/10
- 1/20
- none of these
Hide Answer
Answer: b
Solution:
Log10000^x = -1/4
X= (10000)-1/4
10-1 = 1/10.
21) A men can do a job within 10 days, working 8 hours a day, if women are 33.33% more efficient than the men. How many women will it take to finish the same job in 10days working 6 hours a day?
- 10
- 12
- 15
- 16
- 20
Hide Answer
Answer: e
Solution:
By using formula 🙁 M1D1H1/W1)=(M2D2H2/W2)
(20*10*8/133.33)=(M2*10*6/100)
M2=20.
22) How many 5 digit no. can be formed from 0,2,4,5 & 9?
- 95
- 96
- 120
- 125
Hide Answer
Answer: b
Solution:
5!-4!
We can arrange those five letters in 5! Way, and If 0 comes at the ten thousand places, it will not be a five digit number. So the possibility of getting 0 at the 1st place is 4! Ways. So we need to subtract this 4! From the 5!.
23) What will be the most significant number which divides 37, 59 and 74 leaving remainder 2, 3 and 4 respectively?
- 9
- 2
- 4
- 7
Hide Answer
Answer: d
Solution:
Let, divisor = X.
Dividend = (Divisor � Quotient) + Reminder
Therefor,
37 = (X � Q1) + 2
(X � Q1) = 35 [Where Q1 is a quotient]
Likewise,
(X � Q2) + 3 = 59
56 = (X � Q2) [Q2 = quotient]
(X � Q3) + 4 = 74
70 = (X � Q3)[Q3 = quotient]
Now, since X is the Biggest digit satisfying the given condition, X will be the HCF of 35, 56 and 70.
HCF [35, 56, 70] = 7
Largest number is 7.
24) The number of times four used while writing the numbers from 1 to 100 is:
- 18
- 17
- 21
- 19
Hide Answer
Answer: d
Solution:
In the unit’s place, starting with 4, 14 ….94, we have nine times 4s used.
Also in 40 – 49, we have 2, ten times in the ten’s place.
Hence, total no. of 2s used = 9 + 10 = 19
25) Sum of two numbers is 60, and their product is 120. What is the sum of their reciprocals?
- 3
- 1
- 1/2
- 1/3
Hide Answer
Answer: c
Solution:
Given, a + b = 40 and a*b = 120.
Sum of their reciprocals:
1/a+1/b = (a + b)/a*b= 40/120 =1/2.
26) If 13 + 23 + 33 +…. + 103 = 4050, then find the value of 23 + 43 + 63 + …. + 203.
- 32400
- 80075
- 13100
- 54100
Hide Answer
Answer: a
Solution:
Given, 13 + 23 + 33 +…. + 103 = 4050
23 + 43 + 63 + …. + 203
= 23 (13 + 23 + 33 +…. + 103)
= 8 � 4050
= 32400.
27) In an exam, 30% of the candidates failed in Science and 45% in History. If 20% failed in both Science and History, then what is the percentage of students who passed in both the subjects?
- 55
- 45
- 44
- 50
Hide Answer
Answer: b
Solution:
Let circle M represent students who failed in Science
& Let circle E show students who not passed in History
Unshaped part represents students who passed an exam
Now, % of students failed in Science =n(M) = 30% of students failed in History= n(E) = 45% of students failed in both Science & History = n(M∩ E) = 20
We know that the percentage of students who not passed in either one or both subjects:
n(S ⋃H)= n(S)+ n(H) – n(S ⋂H)
⇒ n(S U H)= 30 + 45- 20
⇒ n(S U H)= 55
∴ % of students who not failed in both subjects = 100 -(% of students who passed in any one subject)
⇒% of students who passed in both of the subjects = 100 – 55 = 45.
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